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In part C of this problem, it asks to compare which has the higher amount of moles. It gives 7.36 x 10^27 atoms of Ru and 7.36 x 10^27 atoms of Fe. I'm confused on how to convert this to moles because the question doesn't give us the mass, only the amount of atoms. The molarity for Ru is 101.07 g/mol and Fe is 55.85 g/mol.
Yes, you can convert the atoms to moles by dividing by Avogadro's number which is 6.022x10^23. Knowing that 1 mol Ru has 6.022x10^23 atoms of Ru, you can divide 7.36x10^27 by 6.022x10^23 to get the moles of Ru which is 1.22x10^4. Doing the same fo 7.36x10^27 atoms of Fe would show you that there are also 1.22x10^4 mol Fe. Thus, both samples contain the same number of moles.
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