E.7 calculate atoms in moles

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Hannah_1G
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E.7 calculate atoms in moles

Postby Hannah_1G » Wed Oct 02, 2019 7:58 pm

The question gives how many carbon atoms are in a molecule of DNA and to calculate in moles how many atoms of carbon there are. Is this asking to divide the number of atoms by moles to be in terms of mole or to multiple the amount of carbon by Avogadro's constant to find the true amount of atoms? Sorry if that doesn't make sense.

Chem_Mod
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Re: E.7 calculate atoms in moles

Postby Chem_Mod » Wed Oct 02, 2019 8:04 pm

This question is essentially asking you to convert some amount of carbon atoms to moles of carbon. The whole DNA part is extra, it is just to give some real world context. To solve this problem, you would convert atoms to moles by dividing the atoms by avogadro's number.

Shutong Hou_1F
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Re: E.7 calculate atoms in moles

Postby Shutong Hou_1F » Wed Oct 02, 2019 8:06 pm

1 mole is the number of atoms in 12 grams of carbon 12, which equals 6.022 * 10^23 (Avogadro constant).
Specifically for this question, I think that it could be solved by dividing the number of carbon atoms by Avogadro constant, according to the definition of 1 mole.

905416023
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Re: E.7 calculate atoms in moles

Postby 905416023 » Wed Oct 02, 2019 8:25 pm

I took the 2.1 x 10^9 atoms of C and divided it by Avogadro's number, or 6.022 x 10^23. This gives you the moles of carbon because you are dividing atoms of carbon by atoms per moles, which leaves you with moles of carbon. You have canceled out the atoms.

Aliya Roserie 4F
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Re: E.7 calculate atoms in moles

Postby Aliya Roserie 4F » Wed Oct 02, 2019 9:37 pm

Shutong Hou_3I wrote:1 mole is the number of atoms in 12 grams of carbon 12, which equals 6.022 * 10^23 (Avogadro constant).
Specifically for this question, I think that it could be solved by dividing the number of carbon atoms by Avogadro constant, according to the definition of 1 mole.



This was very helpful. Thank you for this. I was stuck on a problem that requires using the conversion in regards to atoms and Avogadro's number.


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