Fundamentals E: Moles and Molar Mass Question #27

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Ben 1B
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Joined: Sat Aug 17, 2019 12:16 am

Fundamentals E: Moles and Molar Mass Question #27

Postby Ben 1B » Thu Oct 03, 2019 3:44 pm

What are the steps in solving question E.27 from Fundamentals E: Moles and Molar Mass?
Example:
(a) Calculate the mass, in grams, of one water molecule.
(b) Determine the number of H20 molecules in 1.00 kg of water.

Daria Azizad 1K
Posts: 116
Joined: Thu Jul 25, 2019 12:15 am

Re: Fundamentals E: Moles and Molar Mass Question #27

Postby Daria Azizad 1K » Thu Oct 03, 2019 4:00 pm

a.) Start with the molar mass of a single mole of water by adding the individual molar masses of O and H2

16.00+ 1.01*2= 18.02g/mol

In one mole of water, we know there are 6.02E23 molecules of water, therefore the ratio of water to molecules is 1:6.02E23. Use this to convert from g/mol to g/molecule.

(18.02g/mol)*(1mol/6.02E23mlc)= 2.993E-23g/molecule

b.) First convert kg to g (1kg = 1000g). Then, convert grams of water to moles of water, using water's molar mass. Using the same idea in (a), use the ratio of mlc:mol to convert from moles to molecules.

(1000g)*(1mol/18.02g)*(6.02E23mlc/1mol)=3.34E25 molecules


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