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E 17
Posted: Sun Oct 06, 2019 11:44 pm
by Snigdha Uppu 1G
Which sample in each of the following pairs contains the
greater number of moles of atoms? (a) 75 g of indium or 80 g of
tellurium; (b) 15.0 g of P or 15.0 g of S; (c) 7.36 3 10 27 atoms of
Ru or 7.36 3 10 27 atoms of Fe.
Re: E 17
Posted: Sun Oct 06, 2019 11:46 pm
by Tanmay Singhal 1H
A) 75 g of indium
B) 15 g of P
C) same number of moles
Re: E 17
Posted: Sun Oct 06, 2019 11:47 pm
by Snigdha Uppu 1G
Thank you for answering my question
Re: E 17
Posted: Thu Oct 10, 2019 3:04 pm
by connie 2C
for part a and b, you would use the molar mass of the element to calculate the number of moles in each sample of the element. for part c, you would use avogadro's number to calculate the amount of moles in amount given.
Re: E 17
Posted: Sun Oct 13, 2019 4:55 pm
by Cynthia Rodas 4H
Parts (a) and (b) use the equation m= n * M.
m- mass of the sample
n- amount in moles
M- molar mass
Part (c) uses the equation n = N/NA
n- amount in moles
N- number of objects
NA- Avogadro's constant
Re: E 17
Posted: Sun Oct 03, 2021 12:32 pm
by asheagg3I
a) 75 g of indium.
You would divide the grams given of each element by their molar masses.
75g * 1 mol / 114.81 g = .653 moles indium
75 * 1 mol/ 127.6 g = .587 moles tellerium
b) 15 g of P
(Do the same exact thing).
15 g * 1mol/30.9737 g P = .48428
15 g * 1mol/32.065 g S = .467
c) Equal number of moles.
Both numbers are equal and will get divided by the same number (Avagrado's constant).
Re: E 17
Posted: Mon Nov 29, 2021 12:51 pm
by Nathalia Garibay 1D
A) 75 g of indium
B) 15 g of P
C) same number of moles
For parts A and B you would simply divide the number of grams of the element divided by their molar masses to get the number of moles.
For part C, you are given the number of atoms. To go from atoms to moles, you divide by avogrado's constant. Since the numerator and denominator are both the same, the answer will be the same.