Mass Percent

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Kallista McCarty 1C
Posts: 212
Joined: Wed Sep 18, 2019 12:18 am

Mass Percent

Postby Kallista McCarty 1C » Mon Oct 07, 2019 10:46 pm

What is the mass percent of elements in Sr(NO2)2? How would you go about calculating the mass percent of elements in this equation?

Natalie Nartz 4F
Posts: 50
Joined: Thu Jul 11, 2019 12:17 am

Re: Mass Percent

Postby Natalie Nartz 4F » Mon Oct 07, 2019 10:57 pm

First, you need the molar mass of Sr(NO2)2 which is 179.631 g/mol. Then calculate the mass of each element in the molecule, (Sr 87.62g, N 2(14.01g), O 4(16g)) Finally, take each of the element's masses and divide by the molar mass of strontium nitrate, then multiply by 100 to get the mass percent.

Sr: 87.62g/179.631g= .4878 * 100 = 48.78% Sr
N: 28.02g/179.631g= .1560 * 100 = 15.60% N
O: 64g/179.631g= .3563 * 100 = 35.63% O

Kallista McCarty 1C
Posts: 212
Joined: Wed Sep 18, 2019 12:18 am

Re: Mass Percent

Postby Kallista McCarty 1C » Mon Oct 07, 2019 11:09 pm

Thank you so much!


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