Fundamentals L.1

Moderators: Chem_Mod, Chem_Admin

Lillie Yazdi 3J
Posts: 52
Joined: Fri Sep 24, 2021 6:37 am

Fundamentals L.1

Postby Lillie Yazdi 3J » Thu Oct 21, 2021 12:30 am

I know this seems like a very simple question, but for some reason, I keep getting the wrong answer. Could anyone explain how I would set up my dimensional analysis?

"Without using a calculator, estimate what amount of Br2 (in moles) can be obtained from 0.30 mol ClO2 in the reasion 6ClO2 + 2BrF3 -> 6ClO2F + Br2."

Kurosh Zamiri 1I
Posts: 102
Joined: Fri Sep 24, 2021 6:51 am

Re: Fundamentals L.1

Postby Kurosh Zamiri 1I » Thu Oct 21, 2021 12:44 am

Hi! To set up the dimensional analysis I would start by setting up the molar ratios from the balanced equation. Since we start with 0.30 mol ClO2 and we want to get moles of Br2, we can multiply by 1 mol Br2 / 6 mol ClO2. This results in the moles of ClO2 cancelling, leaving moles of Br2. Then we just do simple math, dividing 0.30 by 6, resulting in the answer being 0.050 moles of Br2 being produced. Hope this helps!

Jessica Cornelia Hongarta 1G
Posts: 114
Joined: Fri Sep 24, 2021 5:49 am

Re: Fundamentals L.1

Postby Jessica Cornelia Hongarta 1G » Thu Oct 21, 2021 2:18 am

Hey! So here, you see that the mole ratio of Br2 to ClO2 is 1 to 6. Use this mole ratio to find the mole of Br2. The tips my TA gave me is to write down the units while doing your calculation (mol Br2, mol ClO2).

1 mol Br2 / 6 mol ClO2 = mol of Br2 / 0.3 mol ClO2
mol of Br2 = (1 mol Br2 / 6 mol ClO2) × 0.3 mol ClO2
mol of Br2 = 0.050 mol Br2

Hope this helps!


Return to “Accuracy, Precision, Mole, Other Definitions”

Who is online

Users browsing this forum: No registered users and 3 guests