s < p < d < f energies

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Hannah Cole 3J
Posts: 41
Joined: Wed Oct 04, 2023 8:24 am

s < p < d < f energies

Postby Hannah Cole 3J » Mon Oct 30, 2023 3:59 pm

I don't understand how penetration and shielding effects lead to s < p < d < f energies, could someone please explain?

Ryka Vahidi 1E
Posts: 85
Joined: Fri Sep 29, 2023 11:10 am

Re: s < p < d < f energies

Postby Ryka Vahidi 1E » Mon Oct 30, 2023 4:51 pm

The Penetration effect can be solved using the quantum numbers and formula. If you solve the formula, you will see that electrons in the s orbital have a high electron probability density near the nucleus, while f electrons have zero electron probability density near the nucleus, which is why the S orbital is near the nucleus and the F orbital is farther away. Furthermore, the shielding effect means that electrons in the S subshell repel the electrons in the P subshell, causing them to be further from the nucleus. Then, the P electrons repel the D electrons, and the D electrons repel the F electrons, causing there to be the different energy levels that we see.


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