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I agree with the other students who have responded; in the equation E = hv, we learned that h is Planck's constant, equal to 6.626 x 10^-34 Js. Thus if you replace that into the equation to solve for the energy of the photon, you are left with E = (6.626 x 10^-34 Js) (v), leaving frequency of the way to be the only variable left to affect the energy. As Jamie said, I agree that if the frequency of the wave increases, then the energy of the photon increases as well!
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