Bohr frequency condition equation

[josephyim1L]

∆E = hv

Hi, for the above equation; can someone explain or give application to finding finding the change in energy level of an electron (∆E)? I'm having a hard time understanding what ∆E means and the nature of its behavior (quantized increases/decreases in energy level).

[Kyle Golden Dis 2G]

When an electron goes from a high energy level and drops to a lower energy level, the difference in energy (ΔE) is given off as a photon.

[Steven Garcia 1H]

The change in energy results from an electron going from one energy level (for instance, a higher energy level farther from the nucleus) to a different energy level (for instance, a lower energy level closer to the nucleus). As a change like this where an electron goes from a higher to lower energy level occurs, energy is released as a photon. If the opposite occurred, then energy is being absorbed. Whether the delta E is positive or negative depends on whether it went to a high energy level or lower energy level. When using this equation, h, Planck's constant will remain the same since it's a constant, so the change in energy varies with the frequency value.