## Wave Length Calculations

Dina Geotas 4A
Posts: 61
Joined: Fri Sep 28, 2018 12:29 am

### Wave Length Calculations

What wavelength values are measurable? For example, why is 1.64 x 10^-38 m not measurable?

Kathryn 1F
Posts: 66
Joined: Fri Sep 28, 2018 12:19 am

### Re: Wave Length Calculations

10^-38m is not measurable simply because it is too small for us to accurately measure at this time. In class, Lavelle said that the threshold for what we could measure was around 10^-13 or 10^15m, which is still very small. For reference, the diameter of an atom is around 1 angstrom, or 10^-10m.

Rhea Churi 4K
Posts: 62
Joined: Fri Sep 28, 2018 12:28 am

### Re: Wave Length Calculations

Conservatively, 10^-18 is when it becomes too small to notice.

Rami_Z_AbuQubo_2K
Posts: 89
Joined: Thu Jun 07, 2018 3:00 am

### Re: Wave Length Calculations

It is too small because the amplitude of the wave and its frequency is so minuscule to detect that it almost seems like it does not exist. Using a number multiplied by 10^-15 or 10^-18 is just the smallest we can actually detect and any smaller is just theory.

Avery Zuelch 1D
Posts: 31
Joined: Fri Sep 28, 2018 12:18 am

### Re: Wave Length Calculations

I think it's crazy that any wavelength smaller than 10^-18 is just a theory. For me, it is hard to grasp the concept that 10^-18 is measurable, but just .000001 smaller than that number is not considered measurable. What is the defining line for measurable vs. non-measurable.

Alexandra Ortega 4D
Posts: 31
Joined: Wed Oct 03, 2018 12:17 am

### Re: Wave Length Calculations

Values smaller then 10^-18 are considered immeasurable because they would be too small to be detected by the technology we have nowadays. That is considered the defining line in our terms. However, that does not mean that wavelengths smaller than that do not exist. We just do not detect them. Only particles with small masses will have detectable wavelengths.