## Wavelength Calculations

duverge_maciel
Posts: 21
Joined: Fri Sep 28, 2018 12:16 am

### Wavelength Calculations

I don't understand where the numbers in the numerator came from that were placed in the equation of the first given example of the lecture. (6.626x10^-34Js)(3.00x10^8m.s-1).

604656370
Posts: 30
Joined: Fri Sep 28, 2018 12:25 am

### Re: Wavelength Calculations

The both are constants. The first number, h, is Planck's constant whereas the second number, c, is the speed of light. And for reference, the formula is $E = hc/\lambda$

lindsey_ammann_4E
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

### Re: Wavelength Calculations

To add to the previous response, we will only be given the equations for E=hv and c=λv, which we must combine to produce E=hc/λ on the test.

Abhi4F
Posts: 30
Joined: Fri Sep 28, 2018 12:28 am

### Re: Wavelength Calculations

When we combine the equations E=hv and c=λv, we get E=hc/λ. Hence, we get the constants, h, Planck's constant (6.626x10^-34Js) multiplied by c, the speed of light (3.00x10^8 m/s).

SophiaKohlhoff4B
Posts: 30
Joined: Fri Sep 28, 2018 12:16 am

### Re: Wavelength Calculations

Will all constants be provided on the test?

Rami_Z_AbuQubo_2K
Posts: 89
Joined: Thu Jun 07, 2018 3:00 am

### Re: Wavelength Calculations

Yes all of the constants will be provided on the test. You should go to the website and find the formula sheet and get familiar with it.