Wavelength Calculations

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duverge_maciel
Posts: 21
Joined: Fri Sep 28, 2018 12:16 am

Wavelength Calculations

Postby duverge_maciel » Sun Oct 14, 2018 11:22 pm

I don't understand where the numbers in the numerator came from that were placed in the equation of the first given example of the lecture. (6.626x10^-34Js)(3.00x10^8m.s-1).

604656370
Posts: 30
Joined: Fri Sep 28, 2018 12:25 am

Re: Wavelength Calculations

Postby 604656370 » Sun Oct 14, 2018 11:29 pm

The both are constants. The first number, h, is Planck's constant whereas the second number, c, is the speed of light. And for reference, the formula is

lindsey_ammann_4E
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

Re: Wavelength Calculations

Postby lindsey_ammann_4E » Sun Oct 21, 2018 2:28 pm

To add to the previous response, we will only be given the equations for E=hv and c=λv, which we must combine to produce E=hc/λ on the test.

Abhi4F
Posts: 30
Joined: Fri Sep 28, 2018 12:28 am

Re: Wavelength Calculations

Postby Abhi4F » Sun Oct 21, 2018 3:00 pm

When we combine the equations E=hv and c=λv, we get E=hc/λ. Hence, we get the constants, h, Planck's constant (6.626x10^-34Js) multiplied by c, the speed of light (3.00x10^8 m/s).

SophiaKohlhoff4B
Posts: 30
Joined: Fri Sep 28, 2018 12:16 am

Re: Wavelength Calculations

Postby SophiaKohlhoff4B » Sun Oct 21, 2018 7:26 pm

Will all constants be provided on the test?

Rami_Z_AbuQubo_2K
Posts: 89
Joined: Thu Jun 07, 2018 3:00 am

Re: Wavelength Calculations

Postby Rami_Z_AbuQubo_2K » Sun Oct 21, 2018 7:37 pm

Yes all of the constants will be provided on the test. You should go to the website and find the formula sheet and get familiar with it.


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