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### Test #2 Question 3C

Posted: **Wed Oct 31, 2018 7:55 pm**

by **Cecilia Jardon 1I**

For this question, I used the kinetic energy formula to calculate the velocity of the electron and got 6.626 x 10 ^-25 m/s. And then used the wavelength = h/mv to find the wavelength of the electron. I plugged in the given and got wavelength= (6.626 x 10^-34 Js) /((9.1095x 10 ^31 kg) (6.626 x 10 ^-25 m/s) ). This gave me the wavelength of the ejected electron to be 1.09 x 10 ^24 m . Is this the correct way to do it? If not, can someone please explain how to do this problem.

### Re: Test #2 Question 4C

Posted: **Wed Oct 31, 2018 10:20 pm**

by **Veronica Soliman 4H**

Hi I haven't received my test 2 back yet, but when I do, I will be sure to reply here. Could you post the actual question on here so I can assist?

### Re: Test #2 Question 3C

Posted: **Thu Nov 01, 2018 11:37 pm**

by **Cecilia Jardon 1I**

In an x-ray photoelectron experiment, chromium metal is irradiated with light of wavelength 9.020x10 ^-11 m

b) How does KE of the e- change as x-ray intensity is increased?

c) Calculate the wavelength of the ejected electron.

Can you please explain both.