Ionization energy

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Marni Kahn 1A
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Ionization energy

Postby Marni Kahn 1A » Wed Oct 09, 2019 10:21 am

Why does the ionization energy generally increase across a period from left to right?

Chem_Mod
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Re: Ionization energy

Postby Chem_Mod » Wed Oct 09, 2019 11:06 am

As you go left to right across a row in the periodic table, you add one proton and one electron going element to element. All of the electrons (negative charge) in that row exist in the same quantum number, or general distance away from the nucleus. However, with each proton (positive charge) you add, the electrons feel a greater attraction to the nucleus. Therefore, more energy is required to remove electrons from an element on the end of a row than one at the beginning, because of a greater attraction.

nickianel_4b
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Re: Ionization energy

Postby nickianel_4b » Fri Oct 11, 2019 5:14 pm

In any one row in the periodic table, all of the elements' atoms have the same number of energy levels. However, going from left to right in one row, the atomic number increases, meaning the number of protons increases. The more protons, the greater the attraction to the electrons, and therefore, the more energy required to remove an electron from the atom (which is the ionization energy).

Alan Wu
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Re: Ionization energy

Postby Alan Wu » Fri Oct 11, 2019 5:40 pm

This may not be the best way to explain it, but it can help you understand this phenomenon better. Elements toward the left of each period have less valence electrons and are more likely to lose them to establish a stable octet. For example, Na only needs to get rid of one electron to achieve a stable octet. Whereas, Cl needs to lose 7 electrons to achieve a stable octet. That's why Na has an ionization energy way lower than Cl.

Marykate Abad 3L
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Re: Ionization energy

Postby Marykate Abad 3L » Sat Oct 12, 2019 2:49 pm

Ionization energy increases from from left to right because elements are more likely to give up their electrons on the right side of the period table.


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