1D.15

Moderators: Chem_Mod, Chem_Admin

SajaZidan_1K
Posts: 56
Joined: Wed Sep 18, 2019 12:15 am

1D.15

Postby SajaZidan_1K » Thu Oct 17, 2019 8:12 pm

1D.15 states "What are the principal and orbital angular momentum quantum numbers for each of the following orbitals: (a) 6p; (b) 3d; (c) 2p; (d) 5f? I understand that the principal number is just the number given, but can someone explain how to find the orbital angular momentum number?

Sophia Shaka 3L
Posts: 57
Joined: Wed Sep 18, 2019 12:20 am
Been upvoted: 1 time

Re: 1D.15

Postby Sophia Shaka 3L » Thu Oct 17, 2019 8:22 pm

Each atomic sublevel has a specific l value associated with it: for s, l=0, for p, l=1, for d, l=2, and for f, l=3. You simply apply this to the given letters.

805307623
Posts: 99
Joined: Fri Aug 09, 2019 12:17 am

Re: 1D.15

Postby 805307623 » Fri Oct 18, 2019 3:17 pm

The principal quantum number "n", describes the electron shell. It increases as the electron energy increases. For example, n = 3 indicates the 3rd shell, and n = 4 indicates the 4th shell. The value of "l" depends on "n". It cannot be larger than one less than "n" (n-1).


Return to “Properties of Electrons”

Who is online

Users browsing this forum: No registered users and 4 guests