Sapling 23

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Jade Lastra 3B
Posts: 51
Joined: Wed Sep 30, 2020 10:06 pm

Sapling 23

Postby Jade Lastra 3B » Sun Nov 01, 2020 10:32 pm

Could someone help me understand exactly how to break down this question and set up the equation?
Screen Shot 2020-11-01 at 10.15.53 PM.png

Valerie Tran 2B
Posts: 53
Joined: Wed Sep 30, 2020 9:48 pm
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Re: Sapling 23

Postby Valerie Tran 2B » Sun Nov 01, 2020 10:35 pm

First, you need to determine E using E = hc/wavelength (use 1064x10^-9) for wavelength. You would get 1.867x10^-19. Then you use the conversion for Joules to eV by dividing E by 1.602x10^-19 to get 1.165eV. Electron affinity is the difference between the incident radiation from the laser and the measured energy of the electrons(0.137eV). So 1.165-0.137=1.028 eV/atom

For the second part just use your conversion factors to change 1.028eV/atom to kJ/mol

Katie Phan 1K
Posts: 93
Joined: Wed Sep 30, 2020 9:55 pm

Re: Sapling 23

Postby Katie Phan 1K » Sun Nov 01, 2020 11:09 pm

Valerie explained it perfectly!
Just find the energy of the light, convert it to eV, subtract the experimentally measured energy of ejected electrons, then convert the electron affinity to kJ/mole.

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