3.21 d and d^10 orbital rule  [ENDORSED]

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AllisonKimbell
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3.21 d and d^10 orbital rule

Postby AllisonKimbell » Sat Jul 02, 2016 1:03 am

Give the ground state electron configuration:
d)Ag+

if Ag is [Kr]4d^9 5s^2, then Ag+ is [Kr] 4d^9 5s^1

the solutions manual has the answer as [Kr] 4d^10

I understand the half full d^5 and full d^10 orbital rule, but to my understanding it is only for Cr and Cu... my TA did this example in discussion with Ag and said something confusing about how the rule stands but only for Cr and Cu and left the electron configuration for Ag as [Kr] 4d^9 5s^2.

Help for this please! Do those rules stand for all of Group 6 & 9 or just for Cu and Cr?

Chem_Mod
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Re: 3.21 d and d^10 orbital rule  [ENDORSED]

Postby Chem_Mod » Sat Jul 02, 2016 1:13 pm

The solutions manual is correct.

All the Group 11 elements Cu, Ag, Au have the same electron configuration for the same reason: d10 s1

All three +1 states have d10.

As I discussed in class we covered the s-block, p-block, and only the 1st row d-block elements.
Therefore Ag and Au would not be asked in a test. Anyway you now have the answer.


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