2.29 c homework

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Camille_Rousculp_3A
Posts: 17
Joined: Wed Sep 21, 2016 3:00 pm

2.29 c homework

Postby Camille_Rousculp_3A » Mon Oct 17, 2016 9:35 pm

How many electrons can have the following quantum numbers in an atom: c) n=2;

How do you know the number of electrons when l isn't given?

Joseph Nguyen 3L
Posts: 24
Joined: Fri Jul 22, 2016 3:00 am

Re: 2.29 c homework

Postby Joseph Nguyen 3L » Mon Oct 17, 2016 10:22 pm

Hello,

When n=2, that means l is equal to 1 or 0 for the p and s orbitals in that n=2 shell. l = n-1 = 2. That means for l = 1, Ml = -1, 0, 1 and for l=0, Ml = 0. Those are two electrons for each of those four orbitals (on Ml is one orbital that can contain two electrons), meaning that there is a total number of eight electrons.

edhuang
Posts: 24
Joined: Wed Sep 21, 2016 2:58 pm

Re: 2.29 c homework

Postby edhuang » Mon Oct 17, 2016 11:32 pm

When n=2 and l isn't given, that means l can be any valid number within n=2. Since l=n-1, l can equal 0 or 1. For 0, it corresponds with the 2s orbital, so 2 electrons there. For 1, it corresponds with the 2p orbitals(3 of them), so 6 electrons there. 2+6=8. Voila


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