Homework Prob 3.37

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Julia Meno 1D
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Homework Prob 3.37

Postby Julia Meno 1D » Sat Nov 04, 2017 6:43 pm

Hi! Can someone explain how they figured out the answer to 3.37? It asks us to identify the element "E" in this Lewis structure, and E is said to be in Period 3.
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Sarah_Stay_1D
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Re: Homework Prob 3.37

Postby Sarah_Stay_1D » Sat Nov 04, 2017 7:03 pm

Julia Meno 1D wrote:Hi! Can someone explain how they figured out the answer to 3.37? It asks us to identify the element "E" in this Lewis structure, and E is said to be in Period 3.


First you just need to count up the total number of electrons in the structure (32 e-). Since there are 3 Cl atoms and we know Cl has 7 valence electrons, 21 of the electrons must be from Cl. There are now 11 electrons left, and 6 of those must be from the oxygen (because it has 6 valence electrons). Now there are 5 electrons left that must come from E. Since the E has 5 valence electrons it must be in group 15. Also, the problem tells you that E is from Period three, which means E must be Phosphorous (P).

Nhan Nguyen 2F
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Re: Homework Prob 3.37

Postby Nhan Nguyen 2F » Sat Nov 04, 2017 10:33 pm

For better understanding,
We know E is an atom that is able to take in more than 4 bonds (as we can see in the structure). Atoms in period 3 or later can accommodate for additional electrons (more than the full 8 electron set!)


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