3.59a
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Re: 3.59a
I had the same question, because when I calculated the formal charges of chlorine and oxygen in the solution's manual configuration I got:
Cl: 7valence electrons - 5 lone pair electrons - 0.5*2 bonding electrons = +1
O: 6valence electrons -6 lone pair electrons - 0.5*2bonding electrons = -0.5
Whereas if I put the radical on oxygen and give chlorine a full octet (with just a single bond between Cl and O), I got:
Cl: 7-6-0.5*2=0
O: 6-5-0.5*2=0
Am I calculating the formal charges the wrong way? Or missing something? Why don't we choose the molecule where the formal charge of each element equals 0?
Thank you!
Anna De Schutter - section 1A
Cl: 7valence electrons - 5 lone pair electrons - 0.5*2 bonding electrons = +1
O: 6valence electrons -6 lone pair electrons - 0.5*2bonding electrons = -0.5
Whereas if I put the radical on oxygen and give chlorine a full octet (with just a single bond between Cl and O), I got:
Cl: 7-6-0.5*2=0
O: 6-5-0.5*2=0
Am I calculating the formal charges the wrong way? Or missing something? Why don't we choose the molecule where the formal charge of each element equals 0?
Thank you!
Anna De Schutter - section 1A
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