3.23 6th Edition

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Alma Carrera 3C
Posts: 33
Joined: Fri Apr 06, 2018 11:02 am

3.23 6th Edition

Postby Alma Carrera 3C » Fri Nov 02, 2018 8:03 pm

This question asks for the maximum positive and negative oxidation numbers that Chlorine can have. The answers are +7 and -1, respectively. Can someone explain to me how these numbers are derived?

Tatum Keichline 2B
Posts: 64
Joined: Fri Sep 28, 2018 12:26 am

Re: 3.23 6th Edition

Postby Tatum Keichline 2B » Fri Nov 02, 2018 8:36 pm

You have to lose 7 (+7) to reach an octet or gain 1(-1) to reach an octet (electrons).

Michael Novelo 4G
Posts: 64
Joined: Fri Sep 28, 2018 12:28 am

Re: 3.23 6th Edition

Postby Michael Novelo 4G » Fri Nov 02, 2018 8:44 pm

If you see where Cl is on the periodic table, it is on period 2, group 17. If we count how many valence electrons it has, (just counting from period 2) you see it has 7 valance electrons. The 7 electrons can either be lost, all 7 of them to form an octet that results in a charge of +7 or it can gain 1 electron 7+1=8 which forms a charge of -1 to fulfill the octet rule. Even though the question doesn't ask, typically for nonmetals they would gain electrons since nonmetals have higher electron affinity, having a charge of negative charge, in the case of Cl it's -1.

Carolina Lechuga
Posts: 33
Joined: Fri Sep 28, 2018 12:17 am

Re: 3.23 6th Edition

Postby Carolina Lechuga » Sat Nov 03, 2018 10:49 am

I don't get the last 2 parts of this question. 3.23 Chlorine can exist in both positive and negative oxidation states. What is the maximum (a) positive and (b) negative oxidation number that chlorine can have? (c) Write the electron configuration for each of these states. (d) Explain how you arrived at these values. Part c and d


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