3.19 (6th edition)

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Lina Petrossian 1D
Posts: 77
Joined: Fri Oct 05, 2018 12:16 am

3.19 (6th edition)

Postby Lina Petrossian 1D » Sun Nov 04, 2018 1:22 pm

3.19 Give the ground-state electron configuration and number of unpaired electrons expected for each of the following ions: (a) Sb3+; (b) Sn4+; (d) Br-; (e) Ni2+.

For part e my answer is [Ar]3d8 with 2 unpaired electrons. Did others get different answers?

Samantha Kwock 1D
Posts: 61
Joined: Fri Sep 28, 2018 12:24 am

Re: 3.19 (6th edition)

Postby Samantha Kwock 1D » Sun Nov 04, 2018 1:33 pm

I believe that should be the right answer as the two electrons that would be removed due to the 2+ positive charge on Ni would be the two electrons in the 4s orbital.

Keshav Bhatnagar 1H
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Joined: Fri Sep 28, 2018 12:17 am

Re: 3.19 (6th edition)

Postby Keshav Bhatnagar 1H » Sun Nov 04, 2018 2:29 pm

If you check the solutions manual, [Ar]3d^8 is the correct answer.

Lina Petrossian 1D
Posts: 77
Joined: Fri Oct 05, 2018 12:16 am

Re: 3.19 (6th edition)

Postby Lina Petrossian 1D » Sun Nov 04, 2018 10:16 pm

Keshav Bhatnagar wrote:If you check the solutions manual, [Ar]3d^8 is the correct answer.

Thank you for clarifying. Unfortunately, I do not have access to the solutions manual.

Destiny Diaz 4D
Posts: 51
Joined: Fri Sep 28, 2018 12:28 am

Re: 3.19 (6th edition)

Postby Destiny Diaz 4D » Tue Nov 06, 2018 6:11 pm

Your work is correct from my understanding, I also got two unpaired electrons for this problem.


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