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My best suggestion is to look at how far away the elements are from each other in the periodic table, therefore looking at the electronegativity difference. Fluorine is furthest from Ag, and you also know that Fluorine is very electronegative.
In order to determine which compound has the bonds with the least covalent character you look at which has the most ionic characteristics. A covalent bond has ionic characteristics when the electrons are not shared equally, which occurs when there is an electronegativity difference between the atoms in the compound (since electronegativity is the electron pulling power). The greater the electronegativity difference is, the more ionic the bond will be. Since electronegativity is based on the distance between the 2 elements on the periodic table you have to look at how far apart the elements in the compounds are. Fluorine and Silver are farther apart (with 3 rows and 6 columns separating them) than Beryllium and Chlorine (where only one row separates them).
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