Question 2D.5

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Tyler Angtuaco 1G
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Joined: Wed Sep 11, 2019 12:16 am

Question 2D.5

Postby Tyler Angtuaco 1G » Mon Nov 04, 2019 9:50 pm

Did this question expect us to have the electronegativity values available? If not, how were you able to determine that CH4 has less ionic character than CF4? And that C and S have closer electronegativities than C and O?

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Joined: Thu Jul 25, 2019 12:17 am

Re: Question 2D.5

Postby 905416023 » Mon Nov 04, 2019 10:08 pm

I think you're just supposed to know by the trend. Like electronegativity increases to the right and up the periodic table.

Sophia Shaka 3L
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Joined: Wed Sep 18, 2019 12:20 am
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Re: Question 2D.5

Postby Sophia Shaka 3L » Mon Nov 04, 2019 10:10 pm

You just have to look at the electronegativity difference between the two atoms, which can be found using the periodic trend. You'll be given the periodic table on the test to use, it can be helpful to circle the atoms and look at their physical distance on the periodic table while thinking about electronegativity. The greater the distance, the more ionic character typically expressed.

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