HW #2.25

Moderators: Chem_Mod, Chem_Admin

Posts: 58
Joined: Sat Aug 17, 2019 12:16 am

HW #2.25

Postby 605379296 » Wed Nov 13, 2019 9:59 pm

Is the answer for a) H3CNH2 and for b) PF in PF3?

I chose H3CNH2 because HCN will have a triple bond, therefore a shorter bond. And for b, I chose PF bond because bond distances increase with atomic size. Since N is a smaller atom than P, I NF3 will have shorter bond distances... Is my reasoning correct?

Posts: 164
Joined: Fri Aug 30, 2019 12:16 am

Re: HW #2.25

Postby sarahsalama2E » Wed Nov 13, 2019 10:02 pm

I had the same reasoning. Bond size also increases/decreases directly with atomic size (i.e. atomic #).

Norman Dis4C
Posts: 101
Joined: Sat Sep 28, 2019 12:16 am

Re: HW #2.25

Postby Norman Dis4C » Sun Nov 17, 2019 11:17 am

Both size and electronegativity affect the result, but since the size of atom follows the same trend as that of electronegativity, PF should have longer bonds.

Return to “Ionic & Covalent Bonds”

Who is online

Users browsing this forum: No registered users and 3 guests