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HW #2.25

Posted: Wed Nov 13, 2019 9:59 pm
by 605379296
Is the answer for a) H3CNH2 and for b) PF in PF3?

I chose H3CNH2 because HCN will have a triple bond, therefore a shorter bond. And for b, I chose PF bond because bond distances increase with atomic size. Since N is a smaller atom than P, I NF3 will have shorter bond distances... Is my reasoning correct?

Re: HW #2.25

Posted: Wed Nov 13, 2019 10:02 pm
by sarahsalama2E
I had the same reasoning. Bond size also increases/decreases directly with atomic size (i.e. atomic #).

Re: HW #2.25

Posted: Sun Nov 17, 2019 11:17 am
by Norman Dis4C
Both size and electronegativity affect the result, but since the size of atom follows the same trend as that of electronegativity, PF should have longer bonds.