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Clarification of Pi Bonds and Rotation

Posted: Wed Nov 21, 2018 4:04 pm
by Nathan Tran 4K
Can someone clarify the point Lavelle made about rotating with pi bonds? I recall he used two pencils to try to rotate the atoms, but I think he said something along the lines of "if there is a pi bond, it means there can be no rotation." Could someone clarify this concept?

Re: Clarification of Pi Bonds and Rotation

Posted: Wed Nov 21, 2018 4:16 pm
by Schuyler_Howell_4D
Pi bonds have electron density on either side of the internuclear axis. This means that because of electron repulsion and the regions of electron density formed by the already present sigma bond, the electrons are "locked" into a region where they can remain. There is no room for the electrons to move around the atom and therefore the bond does not rotate.

Re: Clarification of Pi Bonds and Rotation

Posted: Thu Nov 22, 2018 10:35 am
by Vikramjeet Gill 1C
Pi bonds are formed by the overlapping of two 'spare' p orbitals. This forms a flat bond above and below the sigma bond, this pi bond is only stable in one orientation and if there is any bond rotation then this bond breaks. Pi bonds prevents rotation because of the electron overlap both above and below the plane of atoms.

Re: Clarification of Pi Bonds and Rotation

Posted: Thu Nov 22, 2018 11:06 pm
by Saleha_Mian_3E
What stood out to me is when he said they can not move like sigma bonds because of the density on both sides, which makes them lock into space since there is no way they can rotate. Hope that helps to visualize!