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Hi, Prof. Lavelle stressed the fact that Pi bonds prevent rotation from happening, and if the atoms rotate the bond breaks. Does this mean that a pi bond would normally break before a sigma bond if energy is applied to a molecule?
wait friend I think a sigma bond is stronger not weaker bc they overlap more directly. But going by that logic that does answer my question bc then the pi bond would break first (since it's weaker). I didn't even consider the relative strengths so thank you for bringing it up!
A double bond is stronger than a single bond because of the presence of both a sigma and pi bond, but it is less than twice as strong as a single bond. Although I am unsure, using this line of reasoning it would make sense that a pi bond is weaker than a sigma bond. It makes a bond stronger in a double or triple bond, but not by twice or three times that of a sigma bond.
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