Rotation
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Rotation
If an area of electron density contains a pi bond, is it safe to assume that there are at least two bonds present in the particular area?
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Re: Rotation
Yes, a pi bond can only happen when there is a double or triple bond present between two atoms. Likewise, if there is only a single bond, then you can assume that the bond is a sigma bond.
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Re: Rotation
A single bond is a sigma bond. A double bond is a sigma and a pi bond. A triple bond is a sigma and two pi bonds.
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Re: Rotation
Yes because Pi bonds are only seen in double and triple bonds, where a double bond has 1 pi bond and a triple bond has 2 pi bonds.
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Re: Rotation
Yes. A sigma bond is present in a single bond while a double bond has a sigma and pi bond. A triple bond has a sigma and two pi bonds.
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Re: Rotation
If there is a pi bond, then a sigma bond must be present. I believe there is always a pi bond and sigma bond when there is a double bond or more than a double bond present. Correct me if I'm wrong.
Re: Rotation
Write it in a straightforward way:
single bond = sigma-bond
double bond = sigma-bond + pi-bond
triple bond = sigma-bond + 2 pi-bonds
single bond = sigma-bond
double bond = sigma-bond + pi-bond
triple bond = sigma-bond + 2 pi-bonds
Re: Rotation
Yes, I think so. A single bond only contains sigma bond; a double bond has one sigma and one pi bond. A triple bond has a sigma and two pi bonds.
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Re: Rotation
Yes, if there is a pi bond present, there will at least a double bond or bond with greater strength present.
Re: Rotation
Yes, as long as you know there is one pi bond and not just pi bonds then I think it is safe to assume its at least a double bond.
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Re: Rotation
Yes because in order to have a pi bond, you need to have one sigma bond. For example, a double bond has one sigma bond and one pi bond and a triple bond has one sigma bond and two pi bonds. You won't have only one pi bond.
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