lewis structure of (CH3)2Be

[Susie 2D]

I can't figure out the lewis structure of (CH3)2Be. I think there are 16 valence electrons. 6 from H, 8 from C, and 2 from Be. I've been trying to draw this structure with Be in the center bonded to two carbons but it won't work. What am I doing wrong?

[Raag Desikan 1L]

The lewis structure is as you said with beryllium in the middle with the two CH3 groups bonded to either side of it. I think you might forgetting that beryllium is one of the atoms that doesn't need to have a complete octet. Hope this helps and correct me if I am wrong.

[CristinaG]

Hi Suzie,

you are correct in identifying the 16 valence electrons and putting the Be in the middle. The Be is bonded to the two carbons as you suggested, and each carbon is bonded to three hydrogens. This makes for a total of 8 single bonds within the molecule equalling 16 valence electrons.