Formal Charge vs. Octet  [ENDORSED]

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Formal Charge vs. Octet

Postby Marie_Bae_3M » Wed Oct 19, 2016 4:33 pm

Which is more stable for BF3, as it is with FC all equaling 0 or as a coordinate covalent bond (because boron's formal charge would no longer be 0 then?)?
If the former, why would BF3 react in the first place if it's already stable?

Thank you!!

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Joined: Wed Sep 21, 2016 2:56 pm

Re: Formal Charge vs. Octet  [ENDORSED]

Postby JennaMinami1I » Wed Oct 19, 2016 4:51 pm

Formal Charge = 0 is the most stable, and is an important component in determining the Lewis Structure of a molecule. If we add a double bond to one of the Flourines, the Boron would have an octet but the flourine would have a formal charge of +1, and boron would have an extra electron that it normally doesn't have, giving it a formal charge of -1.

As Dr. Lavelle mentioned in class, Flourine will frequently bond with a F- ion to form BF4- instead of staying as BF3, completing its octet.

Hope this helps!
This website also says similar things to what Dr Lavelle said in lecture if you need some refreshers: ... Octet_Rule

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