Formula for # electrons using Pi-bonds

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JD Malana
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Joined: Wed Nov 16, 2016 3:02 am

Formula for # electrons using Pi-bonds

Postby JD Malana » Sun Jul 23, 2017 11:47 pm

Hi guys, just wanted to share a formula for figuring out how many pi-bonds must be used in a molecule and it goes like this:

P(# of electrons that will use pi-bonds) = 6N + 2 - V

where N is the number of individual atoms in the molecule, excluding Hydrogens
and V is the total number of valence electrons involved.

For example in methanal (CH2O):
P = 6(2 atoms excluding H's) + 2 - (12 available electrons) = 2 electrons need to use a pi-bond, so there will be one double bond

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Re: Formula for # electrons using Pi-bonds

Postby Chem_Mod » Mon Jul 24, 2017 10:14 pm

This is interesting.

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