3 posts • Page 1 of 1
If we draw a Lewis structure and the formal charge isn't zero for multiple different formations, do we draw all of the possible arrangements as a resonance? For example, 3.35b has BrO^- but when you calculate the formal charge with a single bond, O has a -1 charge. When there is a double bond between O and Br, Br has a +1 charge. So if I'm writing the lewis structure, do I write both with double headed angle in between?
There part where you mentioned the double bond and the Br with a +1 charge is actually incorrect. If you form a double bond by taking a pair of electrons from Br, that would mean O would have 10 electrons which can't happen since it has no d-orbital. In this case I think we consider Br the central atom and as in most molecules it is best to have the central atom with a formal charge of 0. If you made a double bond by taking away a lone pair from O, Br would have a charge of -1.
What I understand is that the central atom should try and achieve FC=0 and the other atoms should also try to approach this value if possible. But if there are multiple arrangements where the central atom has FC=0 and the other atoms just interchange charge, then we can show resonance between the structures as each one is stable enough to be used as the correct configuration.
Who is online
Users browsing this forum: No registered users and 1 guest