Midterm Question CH3SH

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Rebecca Cheung 1E
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Joined: Fri Sep 29, 2017 7:04 am

Midterm Question CH3SH

Postby Rebecca Cheung 1E » Sun Nov 12, 2017 3:07 pm

So I bonded carbon with 3 hydrogens and bonded carbon with sulfur (sulfur has 2 lone pairs) and bonded sulfur with hydrogen. It has a total of 14 e-. Just wanted to compare and check if I got this right. Thanks!

Christy Lee 2H
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Re: Midterm Question CH3SH

Postby Christy Lee 2H » Sun Nov 12, 2017 3:08 pm

Yes I got that too.

Stephanie tran 1J
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Re: Midterm Question CH3SH

Postby Stephanie tran 1J » Sun Nov 12, 2017 3:21 pm

the reasoning behind it is because carbon is slightly less electronegative than sulfur; thus, carbon would be the main central atom with 3 hydrogens surrounding it as carbon atoms are larger than hydrogens which will most likely never be the central atom as they are small, highly electronegative atoms that will most often be on the outside of the central atoms.

Shannee Mak 3F
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Re: Midterm Question CH3SH

Postby Shannee Mak 3F » Sun Nov 12, 2017 6:19 pm

This confuses me. I would think that sulfur would be the central atom, as sulfur has a lower ionization energy than carbon. When I look at a chart for ionization energy, carbon is 1086.5 kJ/mol while sulfur is 999.6 kJ/mol.

Would you know that the three H-atoms are bonded to C because of how it's written in CH3SH?

Kayla Ikemiya 1E
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Re: Midterm Question CH3SH

Postby Kayla Ikemiya 1E » Sun Nov 12, 2017 7:39 pm

I got that 3 Hydrogens are bonded to Carbon and Carbon also shares a single bond with Sulfur. Sulfur has 2 sets of lone pairs. Hydrogen is bonded to Sulfur. Carbon is the least electronegative, so it is the central atom. With this configuration the formal charge for each element is 0.

Janet Nguyen 2H
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Joined: Fri Sep 29, 2017 7:05 am

Re: Midterm Question CH3SH

Postby Janet Nguyen 2H » Mon Nov 13, 2017 3:43 pm

Yup that's what I got too! It works out very neatly with every atom having a formal charge of 0 :)


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