Page 1 of 1

### Electron Configuration

Posted: Sun May 06, 2018 8:01 pm
Why does the d-orbital start at 3 while the s and p start off at 1,2,.. and so on?

### Re: Electron Configuration

Posted: Sun May 06, 2018 8:26 pm
The 4s orbitals fill first and have a lower energy than 3d, so the 4s needs to be filled first.

### Re: Electron Configuration

Posted: Sun May 06, 2018 8:26 pm
These numbers are determined by the l quantum number. The l number is the amount of orbitals an element can carry.

### Re: Electron Configuration

Posted: Sun May 06, 2018 8:46 pm
the first shell (n=0) only has one subshell, so it only has s orbitals. after that the second shell (n=1) has two subshells, and therefore has s and p orbitals. the third shell (n=2) has 3 subshells and therefore has s,p, AND d.

### Re: Electron Configuration

Posted: Tue May 08, 2018 10:33 am
KateCaldwell 1A wrote:These numbers are determined by the l quantum number. The l number is the amount of orbitals an element can carry.

how do you figure out the l quantum number

### Re: Electron Configuration

Posted: Tue May 08, 2018 2:06 pm
There isn't a formula to find l number; it is just standard numbers we need to know. s=0, p=1, d=2, f=3. The only other way to solve for it is through n-1= l max.

### Re: Electron Configuration

Posted: Sun May 13, 2018 12:27 pm
d is only present in the 3rd energy level and higher because in each energy level (1-4) an orbital (s p d f) is added. The first energy level only has an s orbital, the second has s and p, and the third has s, p, and d.