3.59a

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victoriatanaka1C
Posts: 38
Joined: Fri Apr 06, 2018 11:05 am

3.59a

Postby victoriatanaka1C » Mon May 21, 2018 8:52 pm

For 3.59a you're supposed to draw the Lewis structure for ClO and in the answer key it says the unpaired electron should be on the Cl. But I drew it on the O, which I thought made more sense because then the formal charge of O would be 6 - 5- 1 = 0 and Cl would be 7 - 6 - 1 = 0. In the answer key, O: 6 - 6 - 1 = -1 and Cl: 7 - 5 - 1 = 1.

How do I know I'm supposed to put the unpaired electron on the Cl?

victoriatanaka1C
Posts: 38
Joined: Fri Apr 06, 2018 11:05 am

Re: 3.59a

Postby victoriatanaka1C » Mon May 21, 2018 9:34 pm

I think it's because O is slightly more electronegative, so it wants to hog that extra e- to get an octet.


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