Electron configuration

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Jasmin Argueta 1K
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Electron configuration

Postby Jasmin Argueta 1K » Thu Nov 08, 2018 6:59 pm

In regards to the question "what is the most likely charge for ions formed for Cd". The answer Is Cd+2 but I'm not sure how. I know the written out you get [kr]4d^105s^2, I'm not sure where to go from there

Jeffrey Xiao 4A
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Re: Electron configuration

Postby Jeffrey Xiao 4A » Thu Nov 08, 2018 7:05 pm

Since it has 2 electrons in its 5s shell, those 2 valence electrons are most likely to be removed to make sure cadmium has a complete octet which is why cadmium's most likely charge is +2.

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Re: Electron configuration

Postby megansardina2G » Thu Nov 08, 2018 7:07 pm

Hi! As you stated, the ground state electron configuration of Cd is [Kr] 4d^10 5s^2. If you want the most likely ion for Cd, you need to take into consideration the electron configurations that are the most stable. The configurations are most stable when the orbitals are either half full or full, so it makes sense that the most likely ion for Cd would be Cd2+, since that would leave the 4d orbital full and the 5s orbital empty, rather than with one unpaired electron. Hope this helps!

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