HW #3.49 (6th Ed)

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Imelda Mena 3I
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Joined: Thu Oct 02, 2014 3:00 am

HW #3.49 (6th Ed)

Postby Imelda Mena 3I » Wed Nov 14, 2018 10:49 am

Hi all!

For this HW problem, why do we have the oxygen in parts a and c have a positive charge of 1 if it is more electronegative than N and C?

Heesu_Kim_1F
Posts: 60
Joined: Fri Sep 28, 2018 12:18 am

Re: HW #3.49 (6th Ed)

Postby Heesu_Kim_1F » Wed Nov 14, 2018 11:54 am

The +1 charge on the Oxygen is referring to the formal charge. For part (a), the total number of electrons is 5 (N) + 6 (O) - 1 (overall +1 charge) = 10 electrons. For part (c), the total number of electrons is C (4) +6 (O) = 10 electrons. For both parts, the only way to fulfill 10 electrons without going over is to place a triple bond between the two elements. When we do that, the formal charge on N and C is 0 and O is +1. I think in cases where there can be different structures that work, you would utilize electronegativity as a tool to find the most stable structure; otherwise, you would not. Hope this helps!


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