Electron configuration

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Jasmin Argueta 1K
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Electron configuration

Postby Jasmin Argueta 1K » Fri Nov 16, 2018 12:00 am

For the test question asking for the ground state configuration of [Ar]3d^104s^24p^3 I keep getting germanium +1 can someone please explain

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Joined: Fri Sep 28, 2018 12:25 am

Re: Electron configuration

Postby julia_lok_2K » Fri Nov 16, 2018 9:16 am

You would first find the element with that ground state configuration, which would be As. Then, since you are looking for the ion of +1 charge, that means the ion lost an electron, so you would look at the element that is to the right of As, which is Se. Therefore, the answer is Se+.

Hope this helps!

Nicholas Kull_3L
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Re: Electron configuration

Postby Nicholas Kull_3L » Fri Nov 16, 2018 9:17 am

It is Selenium because the ion has a +1 charge with the given electron configuration. Starting in the 4th period, the s and d orbitals are full (4s^2 followed by 3d^10), so we can immediately focus on the p orbital. There are three electrons in the p orbital after the +1 charge is taken into account which means your mistake was removing an electron from 4p^3 to get germanium when the removed electron has already been taken into account. Selenium is the answer because its ground state is 4p^4 but the +1 ion makes it 4p^3.

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Re: Electron configuration

Postby ThomasLai1D » Fri Nov 16, 2018 9:19 am

I think you are confusing cations with anions. Cations are ions that lose electrons (yielding a + charge), whereas anions are ions that gain electrons (yielding a - charge). Therefore, germanium +1 would have an electron configuration of [Ar] 3d10 4s2 4p1, not [Ar] 3d10 4s2 4p3.

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