2B.1b
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 119
- Joined: Sat Aug 17, 2019 12:15 am
Re: 2B.1b
The structure that you have drawn has formal charges of 0 on the Cl and O, however the C has a formal charge of +2 since it only has 2 bonds. It also shows 26 valence electrons instead of 24.
In order for the formal charges on all the elements to be 0, Carbon must be placed in the middle and have a double bond with oxygen. This would satisfy the HONC 1234 rule where carbon gets 4 bonds and oxygen gets 2.
In order for the formal charges on all the elements to be 0, Carbon must be placed in the middle and have a double bond with oxygen. This would satisfy the HONC 1234 rule where carbon gets 4 bonds and oxygen gets 2.
-
- Posts: 87
- Joined: Sat Aug 24, 2019 12:15 am
Re: 2B.1b
In general dont forget that we draw the structure around the least electronegative element. In this case it is carbon and therefore for this reason it will be the structure we draw around. Generally, carbon likes to form four bonds and the other three elements will allow it to bond this way with a double bond if necessary. The majority of organic compounds will maintain carbon as the central atom.
-
- Posts: 137
- Joined: Thu Jul 25, 2019 12:17 am
Re: 2B.1b
Most of the time, C should have 4 bonds around it since it's most stable that way. Also, since C also is your central atom. In addition if you draw C in the middle with one side double bond to O and two sides, each bond with one Cl, everything's formal charge would be 0.
Who is online
Users browsing this forum: No registered users and 8 guests