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How do you determine the number of valence electrons in the d subshell? On A.1 part c, they asked for the number of valence electrons in Manganese and the answer was 7. How did they get to this answer?
The number of valence electrons is all of the electrons that are not a part of the inner core. Therefore any electron past the abbreviation we used with [X] where X is a noble gas, will be a valence electron regardless of its subshell or energy level for our purposes in calculating the amount of valence electrons. Therefore in Manganese, where the configuration would be [Ar] 3d5 4s2 we can count seven past the argon. Hope this helps!
As this (https://www.quora.com/Why-does-titanium ... in-group-3) answer to a similar question explains, even though the 3d electrons are not in the n=4 level, their energy is so close to that of the 4s electrons that all are considered valence electrons that can participate in bonding.
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