Midterm Q8

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mayapartha_1D
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Joined: Fri Sep 29, 2017 7:07 am

Midterm Q8

Postby mayapartha_1D » Sun Nov 19, 2017 9:00 pm

Can anyone explain why exactly the HOCO compound has the Lewis structure that it does? Why is it not classified as a radical?

miznaakbar
Posts: 55
Joined: Thu Jul 13, 2017 3:00 am
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Re: Midterm Q8

Postby miznaakbar » Sun Nov 19, 2017 9:57 pm

HOCO is actually supposed to be a radical, and the single electron lies on the Carbon. For the structure of HOCO, you would have a single bond between H and O, a single bond between O and C, and then a double bond between the C and final O. You need to test out different combinations of double and single bonds and to make sure that your structure obeys the octet rule (except for the C since it has a single electron) to get this structure. For a visual, you can look at #123 in the solutions manual for this chapter. Hope this clears things up!

Diane Bui 2J
Posts: 61
Joined: Sat Jul 22, 2017 3:00 am

Re: Midterm Q8

Postby Diane Bui 2J » Sun Nov 19, 2017 11:08 pm

Just to add on, HOCO is a radical because if you count up the total number of valence electrons, it is an odd number of electrons, meaning that there is one lone pair of electrons in the molecule and in this case, it would go on the Carbon. On the midterm, I personally played around with the electron placement, but I realized that putting the lone pair on the Carbon atom results in all the atoms having a formal charge of 0, which represents the greatest stability, as opposed to putting the lone pair on the Oxygen.


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