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Doctor Lavelle mentioned both ways of drawing resonance structures. I don't know that one is necessarily better, but since in the examples we've been drawing the structures out separately with the double-sided arrows, we should probably stick with that :)
To find the resonance structure that is the "best" or most stable we first look at the number of covalent bonds. The greater the number of bonds, the greater the stability of the structure as more atoms will have a complete octet. Additionally, the structure with the least number of formal charges and the least separation of formal charges will be more stable. Hence, a structure with formal charges of (0, 0, 0) would be more stable than a structure with (+1, -1, 0).
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