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The structure with the least number of formal charges is more stable. Also, the most stable resonance structure will have negative charges on the most electronegative atoms and positive charges on the least electronegative atoms (of course, the most stable resonance structure will have a full octet on every atom).
I beileive that it will be the resonance structure thats formal charge is closest to 0. (you can find formal charge of an atom by subtracting the total # of shared electrons/2 + # of lone electrons from the # of valence electrons the atom holds
Everyone is saying that it would be the one with formal charges closest to 0, but as we see in sapling #4 this is just a guideline! The only real way (that we know of so far) is to observe the bond lengths experimentally.
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