## Sulfur Dioxide?

$FC=V-(L+\frac{S}{2})$

StephanieDoan3B
Posts: 21
Joined: Fri Sep 29, 2017 6:07 am

### Sulfur Dioxide?

Why are there three resonance structures for SO2 when the one with two double bonds has the lowest formal charge? Why would the other two structures (one double, one single) be allowed to exist when they have higher formal charge?

RaviAmin1H
Posts: 20
Joined: Thu Jul 13, 2017 2:00 am

### Re: Sulfur Dioxide?

This is because there are two resonance structures that are possible, but they are not as common and this can be shown through formal charge. They contribute to the resonance structure in small amounts. The third structure with the least formal charge is the best blend of all three and contributes the most to the structure.

snehabhargava
Posts: 52
Joined: Thu Jul 13, 2017 2:00 am

### Re: Sulfur Dioxide?

A sulfur dioxide molecule is always changing so in reality it is a blend of all 3 but it is in the state with the lowest formal charge the majority of the time.

204918982
Posts: 50
Joined: Fri Sep 29, 2017 6:04 am

### Re: Sulfur Dioxide?

The two resonance structures can exist because the actual structure is a blend of all three, even though most of the time the sulfur dioxide molecule is in the state of the one with the formal charge of zero.