3.59  [ENDORSED]


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Noah Carey 1G
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3.59

Postby Noah Carey 1G » Tue May 15, 2018 1:19 pm

In chlorine monoxide ClO, when Cl has the radical, the formal charge of Cl is +1 and the formal charge of O is -1. Right? If O is given the radical then the formal charges are 0. Why does Cl have the radical?

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Re: 3.59  [ENDORSED]

Postby Chem_Mod » Tue May 15, 2018 5:43 pm

There is debate on this answer.

The link below from NIST has the asterisk (which notes the radical) is on the O, not Cl.

https://webbook.nist.gov/cgi/inchi?ID=C ... &Mask=1000

Unpaired e- on oxygen results in a formal charge of zero for both the O and the Cl atoms.

We will defer to formal charge and NIST and take the answer as an unpaired electron on the oxygen atom.

Good question.


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