## 3.59 [ENDORSED]

$FC=V-(L+\frac{S}{2})$

Noah Carey 1G
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### 3.59

In chlorine monoxide ClO, when Cl has the radical, the formal charge of Cl is +1 and the formal charge of O is -1. Right? If O is given the radical then the formal charges are 0. Why does Cl have the radical?

Chem_Mod
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### Re: 3.59  [ENDORSED]

There is debate on this answer.

The link below from NIST has the asterisk (which notes the radical) is on the O, not Cl.