3.67 part b

$FC=V-(L+\frac{S}{2})$

Noah Carey 1G
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3.67 part b

Why is ClO2 not more stable with a double bond on O and only 1 electron on Cl? The formal charge of the oxygen will turn to 0. Is it not more stable because this will make Cl's formal charge higher?

Chem_Mod
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Re: 3.67 part b

There are three resonance structures for ClO2 that have a formal charge of zero on each atom:

•O-Cl=O
O=Cl-O•
O=Cl=O

with two lone pairs on each atom except the last Cl (one lone pair). This suggests the radical is delocalized across all three atoms (which is actually more accurate).