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If we have for example XeF4 (ch. 3.65 6th ed), the formal charge on Xe is zero; however, when we’re looking at the bond pairs and lone pairs there’s 12 electrons around the Xe. Will the charge for atoms w expanded valence shells always be 0?
Usually, I think that the purpose of the expanded valence shell is to get the formal charge of the central atom to be neutral. But I'm not sure if it's necessarily that all atoms with an expanded octet when bonded to other atoms will have a formal charge of 0. When you're looking at XeF4 particularly, there's still technically 8 valence electrons around Xe (which fulfills its octet and allows for the formal charge of 0), not 12 because when counting formal charge you count electrons in the bond as 1 not 2. So with 4 bonds and 4 extra electrons in lone pairs, there is 8 valence electrons and so formal charge is 0 for Xe.
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