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Only the elements past period 3 can have more than the octet, excluding boron. In those cases it's more important to have the most stable molecule, if it isn't an element in or past period 3, focus on filling the octet.
I would have to agree, having the most stable molecule possible would be the priority over the octet rule (especially since the octet rule becomes violated in and after period3 due to expanded octets) although for the most part having the octet for elements before period 3 does contribute to the overall stability of the atom from its formal charge.
You should try to give every atom an octet, then you can see if the formal charges are all equal to zero. If not, then check to see if the central atom is in 3p orbital, therefore, you can violate the octet rule. Most of the times the structure should satisfy both the octet rule and the formal charge.
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